a-2[b-2(c-x)]=2

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Solution for a-2[b-2(c-x)]=2 equation:


Simplifying
a + -2[b + -2(c + -1x)] = 2
a + -2[b + (c * -2 + -1x * -2)] = 2
a + -2[b + (-2c + 2x)] = 2
a + [b * -2 + -2c * -2 + 2x * -2] = 2
a + [-2b + 4c + -4x] = 2

Solving
a + -2b + 4c + -4x = 2

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '2b' to each side of the equation.
a + -2b + 4c + 2b + -4x = 2 + 2b

Reorder the terms:
a + -2b + 2b + 4c + -4x = 2 + 2b

Combine like terms: -2b + 2b = 0
a + 0 + 4c + -4x = 2 + 2b
a + 4c + -4x = 2 + 2b

Add '-4c' to each side of the equation.
a + 4c + -4c + -4x = 2 + 2b + -4c

Combine like terms: 4c + -4c = 0
a + 0 + -4x = 2 + 2b + -4c
a + -4x = 2 + 2b + -4c

Add '4x' to each side of the equation.
a + -4x + 4x = 2 + 2b + -4c + 4x

Combine like terms: -4x + 4x = 0
a + 0 = 2 + 2b + -4c + 4x
a = 2 + 2b + -4c + 4x

Simplifying
a = 2 + 2b + -4c + 4x

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